16x^2-30x+6=0

Solution for 16x^2-30x+6=0 equation:

16x^2-30x+6=0

a = 16; b = -30; c = +6;
Δ = b2-4ac
Δ = -302-4·16·6
Δ = 516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{516}=\sqrt{4*129}=\sqrt{4}*\sqrt{129}=2\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{129}}{2*16}=\frac{30-2\sqrt{129}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{129}}{2*16}=\frac{30+2\sqrt{129}}{32}
$